X^2+36x+99=0

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Solution for X^2+36x+99=0 equation: 



X^2+36X+99=0

a = 1; b = 36; c = +99;
Δ = b2-4ac
Δ = 362-4·1·99
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$


$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-30}{2*1}=\frac{-66}{2}
=-33
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+30}{2*1}=\frac{-6}{2}
=-3
$

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